World: r3wp

mh: In the case above, when you were using 'reduce, you were evaluating 
the first block, in which the second block is just a value.  When 
you evaluate a block value, it is not in turn evaluated:

	>> [i'm not code]
	== [i'm not code]

It's important to remember when you do some deeper evaluation:

	>> code: [[]]  ; block containing a block value
	== [[]]
	>> append code/1 'a  ; modify block value
	== [a]

 >> result: do code  ; evaluate block, block value returned - now 
 referenced by 'result
	== [a]
	>> append code/1 'b  ; modify block value
	== [a b]
	>> result  ; result is referencing the same value
	== [a b]
	>> append result 'c
	== [a b c]
	>> code
	== [[a b c]]


Every value in REBOL is merely referenced to by the language.  Sometimes 
explicitly:

	result: []
	probe result

Or not:

	code: [[]]
	probe code/1

Or both:

	code: [[]]
	result: code/1
	probe same? code/1 result

Thanks Chris, Graham, Izkata   I feel like I half get this, but not 
well enough to be confident yet. I have been trying to create a really 
simple example where two parts of the same block are really the same 
items, so changing either, changes both because I think it will help 
me understand better & that was the behaviour in my original example. 
 Perhaps if I study this for another couple of hours I will get a 
breakthrough with it.  Thanks.

Such as?:

	>> attr: []
	== []
	>> cont: reduce [attr attr]
	== [[] []]
	>> insert attr 'c
	== []
	>> insert first cont 'b
	== [c]
	>> insert second cont 'a
	== [b c]
	>> cont
	== [[a b c] [a b c]]

Note that you can continue to reduce the 'cont block, yet the two 
values remain the same.

Hi Chris, I am slowly getting there I think.  Thanks for additional 
example.

Try this:  Predict the output of these function calls:
foo: func [/local A B][
   A: []
   B: copy []
   print mold append A {a}
   print mold append B {b}
]
foo
foo
foo

;Thanks Izkata, I predicted the outcome correctly. I went on to try 
this:
D: [{bar}]                                        ;; global D
foo1: func [D][D: [] print mold append D {d}]     ;; 
foo2: func [D][D: [] print mold append D {d}]     ;; 
foo1 D  ;; value of global D passed to function (but not used)

foo1 D  ;; function references its own local value of [] to which 
it keep appending {d}
foo2 D  ;; same as foo1 but references its own [] ?pointer? thing
D       ;; still references un changed global D

foo1: func [D][D: [] print mold append D {d}]   ;; rewriting foo1 

foo1 D                                          ;; new foo1 function 
has new [] pointer

foo3: func [][D: [] print mold append D {d}]    ;; D is not passed 
to the function

Foo3          ;; now we are changing global D and making it reference 
foo3 [] pointer 
D             ;; proof global D has changed

;; I think the bit that was making it hard for me to understand was 
that 

;; referencing the same empty block in a function means the actual 
exact function, 

;; a second copy of it even with the same name, sets up a new local 
pointer. And also the unexpected localness confused me.


;; Question, do my comments show that my understanding is now correct 
please?

It looks correct to me

:-) thanks Izkata.. I may be moving forward at last :-)

What is the length limit for a comment line please?  some of my comment 
lines are being intrepreted.  I think it is the length of them.

I'm not aware of any limit.

Are you doing this?

comment {
	mutliple comments?

}

no, just ;; in front of a few very long lines.

well.. as I said, not aware of any limit.  maybe it's your editor?

it is like that because I have a bunch of lines that will become 
a function & I am comparing them in some cases, and excludeing them 
in other cases to debug my code.

well, use 'command { }

comment

;; ownerRule: ["owner "  copy owner to newline  

;; ((if (error? try [StructuredData/(to-word thing)/owner]) [append 
StructuredData/:thing reduce[owner copy[]]])(append StructuredData/(to-word 
thing)/owner compose/deep [(owner)]))

;; ownerRule:   ["owner "  copy owner to newline  (append StructuredData/(to-word 
thing) compose/deep [owner  [(owner)]])]

The comment thing sounds good... I will use that instead.  Thanks.

and you only need a single ;

;; is redundant

Those lines I posted still do strange stuff with a single ;  at the 
beginning.  Could it be a bug with the console?  I do 2 ;; to make 
them stand out more, although syntax highliting does that already. 
Thanks.

when using the console, always use:
 do clipboard://

Thanks, that avoids the anomolie :-)

A tip I picked up off of the Mailing List years ago (thanks to whoever 
it was)
   doc: does [do clipboard]
then you need to just type
  doc
to
  DO Clipboard://

Opps -- one line of code, and 100% of it is in error:-(
  doc: does [do clipboard://]

I put this in my %user.r

paste: does [do clipboard://]

I hace CC to write clipboard://, and load-clip and read-clip as well. 
Very handy.

I also have CDR for change-dir+to-rebol-file.

Hi, is thre a neater way to do this please an avoid so many reduce 
statements please?
QQ: []

func1: func [o1] [append QQ copy/deep reduce [reduce o1 reduce reduce 
[reduce o1]]]
owner: "Luke" 
func1 'owner
[owner ["Luke"]]

func1: func [o1][append QQ compose/deep [(o1) [(get :o1)]]

missing close bracket

And sometimes it can make sense to split things up into multiple 
operations (just food for thought).

func1: func [o1] [append QQ o1  repend/only QQ [get :o1]]

Thanks everyone.  I like the shortcut ideas, once I can find the 
right %user.r file to modify.  I think I probably need to delete 
all copies & start again as because I have downloaded Rebol several 
time in my inital confusion when I first started trying to use it 
my PC is confused.


I have not come across GET before so that seems to be my missing 
link, thanks.

Multiple copies of REBOL is a pain that several of us have.

It's a result of programming with Rebol which tells us to use 'copy 
to be safe

I have no problems with multiple REBOL copies.. I have all REBOL 
exe files in one directory. The latest version named like rebol.exe, 
core.exe and older which I sometimes need as rebview1361031.exe for 
example

I think I was not doing any REBOL installation.. just DOWNLOAD - 
COPY - RUN

I have .r associated with my editor :)

With the shortcut  to do clipboard://  it complains if there is no 
 rebol[]   header.  Do folk only use it for bigger blocks of code, 
rather than a few lines that need testing?  As I suppose pasting 
it straight into the console for small chunks works pretty well? 
Thanks.

do read clipboard://

Thanks

I often put
;rebol []

in front of my code when testing it, then include the rebol [] when 
selecting.

Hi, I have associated .r files with Rebol/view, but when I open my 
.r files I get an error
** Access Error: Cabbot open /c/documents
** Near: do/args script system/script/args


I tried associating .rs with Rebol/View & that works ok...  I suspect 
this is a windowsy problem, any suggestions please?

You need quotes around the association, like this: "%1". Edit the 
file type in the Folder Options control panel.

hope you have XP... cause vista only allows to fix associations thru 
the registry editor  :-(

But that's not hard either.

and you can't set manual paths in shortcuts, only select "installed" 
applications.  >-:(

maybe not if you are used to playing in it, but finding and properly 
setting the registry items for rebol isn't really obvious (especially 
if you add the -qs) options.

But that doesn't affect the associations in the registry :)