World: r3wp
[Parse] Discussion of PARSE dialect
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Steeve 27-Jun-2007 [1933x3] | What about a new word “all” which would allow to parse several successives conditions whatever their order ? |
parse [a: 1 b: 2] [all ['a: integer! | 'b: integer!]] would be true only if it exists successivly [a: integer!] and [b: integer! ] whatever their order | |
need it | |
btiffin 27-Jun-2007 [1936] | Umm...I'm not really a parser but parse [a: 1 b: 2] [set-word! integer! set-word! integer!] returns true. |
Steeve 27-Jun-2007 [1937x5] | yeah but what ? if the entry is [b:2 a: 1] instead |
hum sorry, it works too | |
but if the entry is more complex like [a: 1 huge tight b: 1] and that i want parse all this values in any order ? | |
and in your example , you don't test that we must encounter 'a and 'b | |
i give another one example , more simple i want to parse the serie "ABC" but it could be the serie "BCA" , "CBA" , "ACB" ... any combination so if i could write parse "ABC" [all ["A" | "B" [ "C" ]] , it should be more simple | |
btiffin 27-Jun-2007 [1942] | Again, I'm not a parser, but parse's support of alternates with some and any covers these cases no? |
Steeve 27-Jun-2007 [1943x2] | no |
if you write parse "AB" [some ["A" | "B" | "C"]] | |
btiffin 27-Jun-2007 [1945] | parse "ABC" [ 0 1 "A" | 0 1 "B" | 0 1 "C"] ? |
Steeve 27-Jun-2007 [1946] | you get a true answer, but that not the case |
btiffin 27-Jun-2007 [1947x2] | I think I'm clue'in to what you mean. I'll leave this to the pros... :) |
like my use of 0 1 can be opt... :) | |
Steeve 27-Jun-2007 [1949x2] | anyway, you're example just don't work ^^ |
*anyway your example just doesn't work (fewwww) | |
btiffin 27-Jun-2007 [1951] | Yep. I'm out. Not experienced enough to have piped up... ;) |
Steeve 27-Jun-2007 [1952x2] | and what is your mater ? ;-) |
we can talk of rebcode if you want :-) | |
btiffin 27-Jun-2007 [1954] | Thinking about this one, you'd have to repeat all the alternatives. Defeating the purpose...but I'll bet Chris or Geomol or Anton or... will have a workable solution posted before ya know it. |
Steeve 27-Jun-2007 [1955] | i h'ave many alternatives (all comsuming lot of code) that's not the point, i just think it could be more elegant to have such a command |
btiffin 27-Jun-2007 [1956] | Maybe we could hold side bets on which rebol will come up with the solution first...I'd put money down on Oldes or Volker giving you a workable :) |
Steeve 27-Jun-2007 [1957] | if you say so, i tried many alternatives, but they are all uggly |
Brock 27-Jun-2007 [1958] | try this... parse "AB" [some ["A" | "B" | "C"] | none ] |
Steeve 27-Jun-2007 [1959] | i don't want to parse "AB" but any combinations of "ABC" |
btiffin 27-Jun-2007 [1960] | His works. I tried it without the terminating | none and it spun out, so I didn't mention it :) |
Steeve 27-Jun-2007 [1961x2] | parse "AB" sould return false |
not true | |
Brock 27-Jun-2007 [1963x2] | why would AB return false? |
so it must be three characters? | |
Steeve 27-Jun-2007 [1965x2] | because i want parse the complete serie "ABC" in any combination |
yes 3 characters | |
btiffin 27-Jun-2007 [1967] | What it you put 1 repeats inside the some? |
Steeve 27-Jun-2007 [1968] | write it plz |
btiffin 27-Jun-2007 [1969] | nevermind... just tried it. piping up out of turn again :) |
Steeve 27-Jun-2007 [1970x2] | i just don't understand what you mean |
ah ok, it doesn't work :-) | |
Brock 27-Jun-2007 [1972] | do all three characters need to be present? |
btiffin 27-Jun-2007 [1973] | I tried parse "AB" [some [1 "A" | 1 "B" | 1 "C"] | none] ...returns true |
Brock 27-Jun-2007 [1974] | or can characters be duplicated? |
Steeve 27-Jun-2007 [1975] | no Brock |
Brock 27-Jun-2007 [1976] | the | none handles situations where the rule doesn't apply, so almost everything will return true |
btiffin 27-Jun-2007 [1977] | Brock; Without it it'll endless loop no? |
Steeve 27-Jun-2007 [1978x2] | no |
just never use an ''opt" rule in a some or any block | |
Brock 27-Jun-2007 [1980] | will it just be instances of A B & C? |
Steeve 27-Jun-2007 [1981x2] | one instance of each in any order (but just one instance) |
the awaiting result is a: b: c: false parse "CAB" [some ["A" (a: true) | "B" (b: true) | "C" (c: true)]] if all [a b c ] [print "ok"] | |
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