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World: r3wp

[Parse] Discussion of PARSE dialect

Steeve
27-Jun-2007
[1989x2]
yep
i really think it's not feasible without using counters
Brock
27-Jun-2007
[1991x3]
I think I have it
define a rule;
rule: [1 ["A" | "B" | "C"]]
then parse
parse "cAB" [[rule] [rule] [rule]]
the one indicates that there must be an occurence of one of the three 
characters... supplying the rule then requires three characters to 
be entered.
... but it allows multiple characters... damn
Steeve
27-Jun-2007
[1994]
and it works too with the serie "AAA"
Brock
27-Jun-2007
[1995]
which is bad
Steeve
27-Jun-2007
[1996]
yrp
btiffin
27-Jun-2007
[1997]
parse can change the string as it goes right?  What if you tried 
marking them off with X's as you found them?
Brock
27-Jun-2007
[1998]
I was thinking the same thing, removing each character from a block 
as each rule is processed.
Steeve
27-Jun-2007
[1999]
yeah it's possible but it's like hanging counters, you need to have 
some code to check the result and allowing the parser to continue 
further
Brock
27-Jun-2007
[2000]
so your ideal solution would not use anyting other than parse?
Steeve
27-Jun-2007
[2001x2]
yeah i would use a clean dialect , cause i have many many rules of 
this type
moreover , i just  don't want parse simple series like "ABC"
Brock
27-Jun-2007
[2003x2]
what about a 'unique function or something that tests the string 
for unique characters?
... then parse
Steeve
27-Jun-2007
[2005]
as i said , it was just an example , in fact in my case: "A" "B" 
and "C" are complex subrules, so unique don't apply
Brock
27-Jun-2007
[2006]
I think you've lost me.  So when you say sub-rules, you are really 
saying sub 'parse' rules for your dialect?
Steeve
27-Jun-2007
[2007]
yep
Brock
27-Jun-2007
[2008x2]
Will there be more than three rules possible?  You indicate "A" "B" 
and  "C", but could another instance of this also have a fourth character?
each being unique sub-rules
Steeve
27-Jun-2007
[2010x2]
yep, it's not limited
but when i say complex sub-rules , i mean that i have not to check 
single character only, but complex sentences
Brock
27-Jun-2007
[2012]
so the parse string would be better indicated something like "A B 
C" where each of those characters could be a sentence?
Steeve
27-Jun-2007
[2013]
yep
Brock
27-Jun-2007
[2014]
so this is close, with the exception that it does not allow for easy 
testing of unique terms being passed?
r1: "Sent frag 1"
r2: "Sent frag 2"
r3: "Sent frag 3"
r4: "Sent frag 4"

rule: [1 [r1 | r2 | r4 | r3]]


parse "Sent frag 1 sent frag 3 sent frag 4 sent frag 2" [[rule] [rule] 
[rule] [rule]]
Steeve
27-Jun-2007
[2015]
wrong, same problem ever, if it's the same sentence many time
Brock
27-Jun-2007
[2016]
yes, that's what I stated above, if it wouldn't allow for the same 
value to be passed twice, this would work.
Steeve
27-Jun-2007
[2017]
yep
Brock
27-Jun-2007
[2018x4]
I guess I don't understand why a unique function wouldn't work as 
a test prior to parsing.
;very basic example - 
unique: func [str][
	compare-set: "ABC"

 either "" = difference str compare-set [return true][return false]
]

;;;; and yes, that is very ugly
replace;   either "" =
with:   either empty?
... and of course 'unique shouldn't be used as a name due to Rebol 
already having a unique function.
Steeve
27-Jun-2007
[2022x2]
unique works for the rules which use simple constants, but i said 
it, i use more complex rules
parse data [all [rule1 | rule2 | rule3 | rule4]] 

all rules must apply 1 time and 1 time only  in any order, don't 
focus on what is inside rules (it contains sub-rules which contains 
sub-rules).
btiffin
27-Jun-2007
[2024]
Ok, this is convulted and probably wrong


rule: [copy res subrule (remove/part find subrule compse [| (res)] 
2)]
subrule: ["filler" | "a" | "b" | "c"]
parse "fillerabc" [4 [rule] end]


Remove the alternatives from the rule as you find them...the filler 
is to allow | "a" to be found.
Steeve
27-Jun-2007
[2025]
argh, this is uggly :-)
not better than my current solution using counters
btiffin
27-Jun-2007
[2026x2]
Yep...convoluted and hard to verify all the cases to boot.  :)  I 
wouldn't use it to be honest, but it was teasing my brain too much...
Now, I'll slowly back out of the room...ducking and dodging...  :)
Steeve
27-Jun-2007
[2028x2]
take a whisky on the rocks
i got a beer
Brock
27-Jun-2007
[2030x3]
This has it...
r1: "A"
r2: "B"
r3: "C"

rule: [opt [r1 r2 r3]]

parse "ABC" [[rule] [rule] [rule]]
opt = match zero or one time
don't ask me to explain it, but it seems to meet your sample requirements
Steeve
27-Jun-2007
[2033]
have you tested ? doesn't work at all for many cases
Brock
27-Jun-2007
[2034x3]
>> parse "BC" [[rule] [rule] [rule]]
== false
>> parse "ABC" [[rule] [rule] [rule]]
== true
>> parse "BBC" [[rule] [rule] [rule]]
== false
Steeve
27-Jun-2007
[2037x2]
parse "CBA"  = false
in any order, i said