World: r3wp

but I like to use flat structure and foreach [real name of vars here], 
so I need consistent record length :-)

i do too usually, just suggesting an alternative :-)

hmm, if (length? tmp) <> 7 [append tmp ""] will hopefully help :-)

Pekr for now, just add an extra "," as you parse each row. That will 
give you a consistent length with the current behaviour

oh no, I am at the ends ... so bye bye beautifull oneliners ... I 
just found item which contains set of quotes :-) rebol will not translate 
that and my block is confused once again :-)

foreach line ln-tel-list [append result parse/all join line ";" ";"]

damned, I will delete that contact and I will be done ;-) One contact 
from 3 000 does not count, even if that is secreatery of general 
director :-)

thanks allen, might work ....

but still - should I fill RAMBO bug? Imo rebol should add empty quotes 
automatically, if the line ends with ;

Put it in for Carl to decide. Mention the work around too

why are following quotes causing a trouble? I did not ask rebol to 
take them into accout?

parse/all {test1    ;test2;"test3   "quoted""} ";"

["test1     " "test2" "test 3 " {quoted""}]

that is really completly weird ...

the only delimiter I asked rebol to use was semicolon, so everything 
following test2; should be one element ...

That's a good one for the parse/all test suite. Rambo it.

; same bug again here too.
parse/all {a: b ":" c} ":"
== ["a" { b "} " c"]

OK, submitting ...

; would have expected
== ["a" { b "}  {" c}]

I just remember, that this was discussed already.
The solution was to use something like
 
  split: func [string delim /local tokens token] [
      tokens: make block! 32
      parse/all string [

          any [copy token to delim (append tokens probe token) delim]
          copy token to end (append tokens token)
      ]
      tokens
  ]

sqlab: if 'parse can't do it, 'parse can do it ;)

I have "(name1) - (name2) (result)"

eg. {team one - team two 3,0-3,0}

Any simple solution to split it ["team one" "team two" "3,0-3,0"]?

I've done such a rule:
[copy x to "-" (team1: x)
-
 any " " copy x to " " (team2: x)
 
any [mark: alpha :mark copy x to " " (append team2 join x " ")]
any " "
x: digit to end (result: x)]

How many possibilities are there for the values "team one" and "team 
two"?  Could you use a team repository? --

teams: ["team one" | "team two"]

chars-n: charset "0123456789"
points: [1 4 chars-n "," 1 4 chars-n]
score: [points "-" points]

parse str [teams "-" teams score]

str: {team one - team two 3,0-3,0}  ;-- natch

not really simple but: 

name: complement charset {1234567890-}
score: [integer! "," integer! "-" integer! "," integer!]
str: {team one - team two 3,0-3,0}
rst: copy []
parse/all str [
	2 [copy token some name(append rst trim token) opt "-"] 
	copy token score (append rst token)
]
rst

of course this would preclude names like "team were#1"

Thank You, it's nice to see such a pretty solutions :)

What are the recursion limits on 'parse? Because I just hit it in 
the imap:// protocol ...

Ingo I made simple test and it seems it's something like 512

x: copy [] loop 1000 [append x 1] i: 0 rule: [number! (i: i + 1 print 
i) rule] parse x rule

<Slaps his head> Thanks! I could have thought about just trying it 
myself ;-)

Well, I'll have to try to rewrite the parse rules, then. 512 is by 
far not enough in this case.

the parse limit it will vary with platform

arrg not awake ... recursion limit

make that parse recursion limit, the limit on recursions for functions 
is a _lot_ higher (at least on winxp, view 1.3.1)

I have some problems to translate RULE based on PERL  regular expression 
to rebol parse rules. Maybe this group can help me. For example:
PERL REGULAR EXPRESSION RULE:
[[ c ]] (e|è|é|ê|i|î|y) -> s 

 we need to match the #"c" char and test  the next char to know if 
 we trap S phonem. example "Ce" must be emited S et E. I plan to have 
 2 rules rule: [ .../... "c" etc...  | "e"  etc... ]

More complicated rule:
an [[ c ]] T ->	
like for "banc"

CLASS V [aeiouàâéèêëîïôöùûü]			# voyelles
CLASS C [bcçdfghjklmnñpqrstvwxyz]		# consonnes
CLASS L (V|C)							# toutes les lettres
CLASS P [\,\.\;\:\!\?]					# ponctutions
CLASS N [0123456789]					# chiffres

CLASS W [_&\']+							# espace
CLASS S (^|W|P)							# limite gauche d'un mot
CLASS T ($|W|P)							# limite droite d'un mot

s: "Hello cè World" 
es: charset[#"e" #"è"#"è"#"ê"#"i"#"î" #"y"]

parse/all s [ to "c" p: skip es p2: ( p: change/part p "s" p2 ) :p 
]
? s

questions: 
-long string? then better copy instead of change/part
-more patterns in same path, then not 'to.

Volker that's not what I want to get ...

I'm seeking a rebol ruke that allow me to test the character after 
a key char example #"c" but keeping it into the parsing stack

you know p: and :p in parse-rules?

k I will try it thank u :)

yargh. I know how to split with a single character as the delimiter:

	chunks: parse/all text "^/"


How do I split where a blank line (2 newlines with nothing in between) 
is the delimiter? The naive solution I can think of just doesn't 
work:

	chunks: parse/all text "^/^/"

you can make up a rule.

lines: copy []
rule: [ copy txt to "^/^/" (append lines txt) skip 2 ]
parse mytext [ some rule ]

untested ...

I get lost trying to find a good way to describe my rule. Here's 
the bad code that states my intent, but doesn't work ('parse doesn't 
seem to like having that 'until in there)

chunks: parse/all text [
	until [
		chunk: copy ""
		copy chunk to "^/^/"
		skip
		if chunk [
			append chunks chunk
		]
	] 
]

ummm.. don't think you can do that

nope, I discovered that :-D

parse expects to see a parse dialect if you following it with a block

try my way ...