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World: r4wp

[Rebol School] REBOL School

Endo
7-May-2013
[1922]
There is also request-dir I think.
PatrickP61
7-May-2013
[1923]
I'm using 2.100.111 and no REQUEST-DIR, unless it was added in a 
later version
Cyphre
7-May-2013
[1924]
In Saphirion's build we have REQUEST-DIR already added.
james_nak
7-May-2013
[1925]
I tried request-file in the android build, it didn't crash but nothing 
showed up. Not that I needed it - I was just curious.
Cyphre
7-May-2013
[1926x4]
The android version doesn't have thesee calls implemented yet (AFAIK 
android doesn't have any "default OS" requesters for that so we need 
to do it ourself or reuse custom code)
But in Windows version this works.
It's even in the lates public source release here: http://development.saphirion.com/downloads/
so if anyone have time to make pull-request?
(check the OS_Request_Dir() function in src\os\win32\host-lib.c as 
a base for the feature)
PatrickP61
7-May-2013
[1930x5]
Thanks Cyphre, I've just downloaded from Saphirion -- Looks exciting!
I am trying to troubleshoot a peculiarity in   R3    2.101.0 from 
Saphirion

>> print type? what-dir

file!				<-- Ok, it's a file, even if has an end slash instead of 
a specific file path
>> print type? request-dir	; select any directory
file!				<-- Ok, Same thing


So it stands to reason that passing the value returned by WHAT-DIR 
and by REQUEST-DIR  will be FILE!
So here is my code that is giving me some trouble:

file-list:	[]

read-dir:	func	[
	dir	[file!	]
	] [
	foreach file read dir [
		file: either dir = %./ [file] [dir/:file]
		append file-list file
		if dir? file [
			read-dir file
	]	]	]

inp-dir: request-dir/path	what-dir 

unless inp-dir [ask	">>> No directory selected, cannot proceed  (Enter)" 
 quit ]
cd :inp-dir


read-dir inp-dir		; <-- does not work as expected, must use cd and 
what-dir instead
;read-dir what-dir
new-line/all file-list on
print mold file-list
If you comment out the READ-DIR INP-DIR and uncomment the next line, 
it works fine!

What am I missing?  Another bug?
I'ts getting late, see you tomorrow!
GrahamC
7-May-2013
[1935x2]
what happens when you probe inp-dir after the request?
have you done 'load-gui before you run the script?
Andreas
8-May-2013
[1937x4]
Patrick, simple fix: if you expect INP-DIR do be a file refering 
to a directory, sanitise it through DIRIZE: `read-dir dirize inp-dir`.
The underlying problem indeed is related to a bug in R3. Both directories 
and files are represented by file! in R3. R3 uses a heuristic that 
a trailing slash discernes file file!s from directory file!s. Now 
when you pass a file! without a trailing slash but which actually 
refers to a directory to READ, READ crashes. (Bug#1675)
The simplest demonstration of that bug: read %.
Now if REQUEST-DIR returns a file! without a trailing slash, passing 
that returned value directly to READ will trigger this bug.
PatrickP61
8-May-2013
[1941]
Back again.  Thank you Andreas,


I had realized that FILE! was used for both directory and files, 
but I didn't realize that REQUEST-DIR was NOT sending it back as 
a directory, but as a file (without trailing slash).  I was able 
to confirm by adding a print of WHAT-DIR and INP-DIR and compare, 
as per your comments.

I did not know about DIRIZE


Using READ DIRIZE INP-DIR does fix the problem -- though I wonder 
if REQUEST-DIR should return it with a trailing slash?

Thanks again to all!
Andreas
8-May-2013
[1942]
Yep, I think REQUEST-DIR should return a dirized file!.
PatrickP61
8-May-2013
[1943]
Hey all, I'm having such a good time learning again!


I've got some code to generate a print ruler, but I think it could 
be cleaned up a lot more.   

If some of you have a quick moment, could you take a quick look and 
advise me on how to shorten this code.

ruler1: copy ruler2: ""
idx: 0
loop 110 [
	idx: idx + 1
	append ruler1 "_"
	append ruler2 last-digit: last to-string idx
	if last-digit = #"5" [
		clear back tail ruler1
		append ruler1 "+"
		]	
	if last-digit = #"0" [
		either idx < 99 [clear back back tail ruler1]
			[clear back back back tail ruler1]
		append ruler1 to-string idx
		]
	]
replace/all ruler2 "0" "_"
print ruler1
print ruler2



____+___10____+___20____+___30____+___40____+___50____+___60____+___70____+___80____+___90____+__100____+__110

123456789_123456789_123456789_123456789_123456789_ 123456789_123456789_ 
123456789_123456789_ 123456789_123456789_
GrahamC
8-May-2013
[1944]
Try ++ idx instead of idx: idx + 1
PatrickP61
8-May-2013
[1945x2]
I don't like the BACK BACK ... etc, depening upon the length of IDX 
which is what I want to print out 

Can I do something like LENGTH? IDX and use that number to "back 
up the series"?
I'll give ++ idx a try
GrahamC
8-May-2013
[1947x2]
copy/part tail form idx -1 will give you the last number
shouldn't use mutually exclusive serial if statements
PatrickP61
8-May-2013
[1949]
You mean instead of LAST-DIGIT: LAST TO-STRING IDX
GrahamC
8-May-2013
[1950]
yes
PatrickP61
8-May-2013
[1951x2]
Should I use FIND instead?
How can I use the LENGTH? of IDX as a way to CLEAR those last positions.


ie IDX is 110, length is 3 then clear the last 3 characters from 
the ruler1 series and replace with to-string idx
GrahamC
8-May-2013
[1953]
try ? 

clear skip tail series -3
PatrickP61
8-May-2013
[1954]
Thanks Graham,


I'm getting an error with ++ idx,  help ++ indicates incrementing 
a 'word, but I'm not understaning it
I'll try your suggestions
GrahamC
8-May-2013
[1955]
>> idx: 1
== 1
>> ++ idx
== 1
>> idx
== 2
PatrickP61
8-May-2013
[1956]
:-D   Oh my gosh, i couldn't get copy/part tail form idx - 1 working 
because I thought it was IDX subtract 1.  Ooops, you meant -1 as 
part of copy/part!!!!
Bo
8-May-2013
[1957x2]
>> help copy
USAGE:
    COPY value /part range /deep


So, copy/part takes two parameters:  (1) the start index, and (2) 
the range


If you rewrite the copy/part like I did below, it is much easier 
to see how it is split up:

copy/part
	tail form idx	;parameter 1
	-1		;parameter 2
I'm not saying to use that format for writing your scripts, but as 
a visual aide, it may help.  Also, you could make it kind of lisp-y 
like this:

copy/part (tail form idx) (-1)
PatrickP61
8-May-2013
[1959]
Yes, thank you Bo,  I like the lisp-y version!!!
Bo
8-May-2013
[1960]
I sometimes do that when I am trying to debug a lot of nested statements, 
because if you use parens, Rebol will let you know that it didn't 
receive something it was expecting instead of just pulling the output 
from the next nested statement.
PatrickP61
8-May-2013
[1961]
I've found that it is very easy to nest inside of statements, but 
hard to remember what goes where!!!    I like your suggestion!  :-D
Bo
8-May-2013
[1962x2]
Actually, the first method I posted above is easier to understand 
for a lot of nested statements.  Compare this real line of script 
from one of my programs.

The way I normally write it:

browse probe rejoin copy [http://www.respectech.com/log/show-invoice.cgi?user=
username "&pass=" password "&submit=" replace/all client "&" "%26" 
"&invno=" invnum either amtdue [rejoin ["&notice=1&amtdue=" to-decimal 
amtdue "&daysdue=" daysdue]][copy ""]]

Lisp-y:

browse (probe (rejoin (copy [http://www.respectech.com/log/show-invoice.cgi?user=
username "&pass=" password "&submit=" (replace/all (client) ("&") 
("%26")) "&invno=" invnum (either amtdue [rejoin ["&notice=1&amtdue=" 
(to-decimal amtdue) "&daysdue=" daysdue]][copy ""])])))


Heirarchical (takes a lot more space, but is easier to follow -- 
however, doesn't have the parameter enforcement of parens):
browse
	probe
		rejoin
			copy
				[
					http://www.respectech.com/log/show-invoice.cgi?user=
					username
					"&pass="
					password
					"&submit="
					replace/all
						client
						"&"
						"%26"
					"&invno="
					invnum
					either
						amtdue
						[
							rejoin
								[
									"&notice=1&amtdue="
									to-decimal
										amtdue
									"&daysdue="
									daysdue
								]
						]
						[
							copy
								""
						]
				]
I'm glad we don't have to use the Lisp method or the heirarchical 
method, but it is nice that we can, especially when we are starting 
out.  I usually only use the heirarchical method when I am trying 
to understand and visualize someone else's really complex scripting. 
 I'll use the Lisp method when I am getting an error that I have 
narrowed down to a small snippet of code, and I can't figure out 
why the error is occurring.  I also throw in a lot of 'probe statements 
to see what's really going on.
Ladislav
9-May-2013
[1964x3]
Patrick,

    clear back tail ruler1
    append ruler1 "+"

actually is

    change back tail ruler1 #"+"
Similarly,

		either idx < 99 [clear back back tail ruler1]
			[clear back back back tail ruler1]
		append ruler1 to-string idx

can be written as

		change skip either idx < 99 [-2] [-3] to-string idx
err, I lost a part of the expression:


    change skip tail ruler1 either idx < 99 [-2] [-3] to-string idx
Gregg
9-May-2013
[1967x2]
Patrick, rather than building up the strings bit by bit, consider 
how you might do it if you think of them as a buffer you're modifying. 
e.g., start with something like this:

ruler1: copy ""
insert/dup ruler1 "_" 110
forskip ruler1 5 [change skip ruler1 -1 "+"]

or this

ruler1: head insert/dup copy "" "____+" 22
Sometimes things aren't clearer when you reduce them, but sometimes 
it can work well.
PatrickP61
9-May-2013
[1969x2]
Thank you Bo, Ladislav, and Gregg  -- I'll use all your suggestions 
:-)
Thanks to all that helped. Learning all the time.  I think I have 
the code pretty tight now!  A lot better than my first attempt.  
Final solution:

ruler-len: 80

ruler-1: head insert/dup (copy "") "----+----."	to-integer (ruler-len 
+ 9 / 10)
ruler-1: head clear (skip ruler-1 ruler-len)		; trim excess
r1: skip head ruler-1 9				; adv to pos 10
forskip r1 10 [	adj: ((length? idx: to-string (index? r1)) - 1)
				change skip r1 (-1 * adj) idx		]
ruler-1: head r1					; r1 is at tail

ruler-2: head insert/dup (copy "") "123456789." to-integer (ruler-len 
+ 9 / 10)
ruler-2: head clear (skip ruler-2 ruler-len)	; trim excess
print-ruler:	does [print ruler-1 print ruler-2]
Ladislav
10-May-2013
[1971]
My notes:


* it is absolutely unnecessary to set RULER-1 three times to the 
same value thus, I normally do:

    ruler-1: copy ""

    insert/dup ruler-1 "----+----." to-integer (ruler-len + 9 / 10)
    clear (skip ruler-1 ruler-len)		; trim excess
    ....
    ; for the same reason it is unnecessary to do:
    ; ruler-1: head r1