World: r4wp
[!REBOL3] General discussion about REBOL 3
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BrianH 13-Mar-2013 [1978x2] | Then start-vs-end sets the direction, and bump sets the velocity. It's just a way to explain *why* to newbiees. |
Dealing with the consequences of triggering an error is more expensive, so we tend to only want to trigger errors when they really *are* errors. If there is a plausible way to just do nothing and/or return none when it's not potentially damaging, we should come up with a rationale that lets do that instead. | |
Ladislav 13-Mar-2013 [1980] | You can say that you "support" zero velocity by "not looping", but, in fact, you rather don't support it by failing as silently as possible. |
BrianH 13-Mar-2013 [1981] | It's really a rationale. |
Ladislav 13-Mar-2013 [1982x2] | No problem to say it is "zero velocity". The problem is that in "normal life" something having zero velocity does not "vanish", rather it stays where it is. |
So you may be caught as using "inappropriate logic", but I do not mind, being able to eventually answer that it is an exceptional case that you simply did not want to handle to not cause headaches to some users, while causing inconveniences to people being able to calculate what it is they should have expected. | |
BrianH 13-Mar-2013 [1984] | We can just arbitrarily declare that we want 0 velocity to be considered out of range, as a favor to the developer, and the velocity explanation gives us a good excuse to not trigger an error. FOREVER existing means that they have other options, and index setting means that they can do whatever they want if they really want to, so it's not actually a constraint if they don't want it to be. |
Ladislav 13-Mar-2013 [1985] | You can always declare something arbitrarily. The problem is that if you do declare a + b = none in case a = 0 you are most probably causing inconveniences to all people knowing that there might have been a more consistent behaviour... |
BrianH 13-Mar-2013 [1986] | Remember, #864 is a proposal to replace FOR with a more flexible power-user function that would be less safe to use. They lose some safety as a tradeoff for more power and prettier sytnax. So, they lose two features (safety and backwards compatibility) but gain more flexibility. The greater flexibility would come at the expense of a slower function: negligably in the case of the function itself, but more when you add the conditional wrapper code, so it would have to be used carefully if you want it to be efficient. Overall, that is the R3 motto right there: R2 is for newbies, R3 for power users. |
Ladislav 13-Mar-2013 [1987] | But let's just forget about it in this specific case. I guess that FOR is not expected to be used extensively anyway. |
BrianH 13-Mar-2013 [1988] | So, I would recommend that the #1993 restrictions against accidental infinite loops should go into R3/Backwards and rebol-patches, because R2 is for newbies. And I would recommend that #864 be the new FOR for R3 and R2/Forward, because R3 is for power users. |
Gregg 13-Mar-2013 [1989] | Man, you guys are typing faster than I'm reading. :-) |
Ladislav 13-Mar-2013 [1990] | LOL |
Gregg 13-Mar-2013 [1991x2] | the best you can do is to cause an error when finding out that all [start = end bump = 0] is TRUE, since in that case there is no reasonable terminating condition that could not cause infinite loop by default. I think this answers what I was asking. Though it seems that Ladislav wants [1 1 0] to be infinite for consistency, while Biran and I want it not to be, for perceived user friendliness. :-) |
Brian, for that case, does your model make it a "no loop" or "once only" condition? | |
Ladislav 13-Mar-2013 [1993] | Gregg, we just agreed to make it "no-loop" |
Gregg 13-Mar-2013 [1994] | OK, I skimmed too fast. Thanks. |
Ladislav 13-Mar-2013 [1995x2] | (which is "the most silent failure") |
once only would be rather inconsistent with any terminating condition, because there is none that could cause it to loop exactly once | |
Gregg 13-Mar-2013 [1997x2] | Updting %new-loop.r now. |
Posted %mezz/new-loop.r | |
BrianH 13-Mar-2013 [1999x3] | Gress, for the start-vs-end-sets-direction bump-is-velocity model: * start=end means no direction so just loop until the =end termination condition is met and ignore bump. If the index gets changed in the body block, let the =end termination condition handle it. * start<end means positive direction, for values of "positive" that don't include 0, so bump <= 0 is out of range, meaning no loop. The termination condition *if we start looping* is >= end. * start>end means negative direction, for values of "negative" that don't include 0, so bump >= 0 is out of range, meaning no loop. The termination condition *if we start looping* is >= start. Positive and negative directions don't include 0 because if the developer wanted to do an infinite loop they would have used FOREVER or R3's #864 FOR general loop. R2 was aimed at newbies, and they need extra coddling. |
Gress -> Gregg | |
For the bump-sets-direction start-and-end-set-the-range model, 0 doesn't set a direction so it should trigger an error. Otherwise, the same. | |
Gregg 13-Mar-2013 [2002] | Brian, can you point out which test case is incorrect, and what it should produce? That way we can match against Ladislav's examples. |
BrianH 13-Mar-2013 [2003] | I like the model that doesn't trigger an error. |
Gregg 13-Mar-2013 [2004] | And I tested %new-loop.r only under R2, not R3, just in case. |
BrianH 13-Mar-2013 [2005x3] | Test cases for the first model, just using literal numbers as metaphors for the principles: ; start = end, start is not constrained, termination is x = end [i: 0 1 = for x 5 5 1 [if i >= 1 [break/return 'fail] i: i + 1]] [i: 0 1 = for x 5 5 -1 [if i >= 1 [break/return 'fail] i: i + 1]] [i: 0 1 = for x 5 5 0 [if i >= 1 [break/return 'fail] i: i + 1]] ; start < end, start is x >= end, termination is x >= end [i: 0 2 = for x 4 5 1 [if i > 2 [break/return 'fail] i: i + 1]] [none? for x 4 5 -1 [break/return 'fail]] [none? for x 4 5 0 [break/return 'fail]] ; start > end, start is x <= end, termination is x <= end [i: 0 2 = for x 5 4 -1 [if i > 2 [break/return 'fail] i: i + 1]] [none? for x 5 4 1 [break/return 'fail]] [none? for x 5 4 0 [break/return 'fail]] In all cases, bump is added to x after the termination condition is not met and before looping again. |
Let me fix some comments above: ; start < end, start is bump > 0 and x >= end, termination is x >= end ; start > end, start is bump < 0 and x <= end, termination is x <= end So, the direction sets the termination condition, and the bump sets the velocity that the loop is advanced between iterations, with range limits on the velocity as a starting condition in addition to the end range limits. | |
Ugh, let me fix the comments again, AltME is annoying: ; start < end, start is bump > 0 and x <= end, termination is x >= end ; start > end, start is bump < 0 and x >= end, termination is x <= end | |
Gregg 13-Mar-2013 [2008] | Thanks. I'll have to make time to reconcile those with the tests I have in there now. I was hoping you could just say which don't match your model. |
BrianH 13-Mar-2013 [2009] | I kind of don't have time for that. I'm on the clock doing something non-Rebol-related. |
Gregg 13-Mar-2013 [2010x2] | OK. |
If you get a chance, it runs the tests and just outputs to the console, so you can, I hope, see quickly where it goes off. | |
BrianH 13-Mar-2013 [2012x3] | Well, when I get the chance I would like to review all of the FOR tests. But the question is whether at this stage of the game we should change tests for an R2 function. R3/Backwards and rebol-patches make R2 fixes relevant again, and this change is in keeping with R2's target market (newbies), but I don't know whether FOR's behavior is important enough to make it worth fixing in the tests, or important to keep bug-for-bug compatible (does anyone actually use it?). For R3, the tests will probably end up having to be redone for #864 FOR. |
R2's original target market was newbies, but it kinda failed to hit that market. So at this point R2's target market is existing R2 users. | |
Is there even a significant number of existing R2 users who even use FOR at all? I mean, it really was crappy in R2. I definitely want to fix this in rebol-patches just on general principle, and likely R3/Backwards too since they're supposed to be compatible with each other, but does it even make sense to have a regression test for R2 if we're not going to have new versions? Are the R2 tests supposed to be testing rebol-patches and R3/Backwards, or new R2 versions that may never exist? | |
Gregg 13-Mar-2013 [2015] | I don't think we can know, aside from scanning rebol.org and asking people. I use it sparingly. |
Sunanda 14-Mar-2013 [2016] | Over 10% of scripts at Rebol.org seem to use FOR. (135 out of 1152). That's an upper bound as there may be a few false hits if someone is using 'for as a word etc....The search URL below finds the word FOR where it is in the body of a script (ie not in a comment, string or header) www.rebol.org/search.r?Find=[b]for |
Ladislav 14-Mar-2013 [2017x4] | Hmm, to my big surprise I found my script in the list. But, after checking, FOR appeared really just in the COMMENT. |
* start=end means no direction so just loop until the =end termination condition is met and ignore bump. If the index gets changed in the body block, let the =end termination condition handle it. - that is not reasonable for BUMP = 0 (no consistent termination condition can be defined for that), also, the termination condition should be VALUE <> END in this case if you want to be consistent | |
(the "no consistent TC" means no termination condition consistent with your requirement to not loop infinitely) | |
And =end is not a termination condition because you want the cycle to run at least once | |
Sunanda 14-Mar-2013 [2021] | Sorry.......As I said, some false hits - no easy way to exclude comment [....] from searches. When I said it excluded comments, I meant ; comment |
Ladislav 14-Mar-2013 [2022x6] | understood, no problem |
Brian, =end is not a termination condition, see these examples: for i 5 5 1 [print i i: -5] ; this should print 5 and terminate for i 5 5 1 [print i i: 3] ; this should be print 5 and terminate for i 5 5 1 [print i i: 4] ; this should be an infinite loop for i 5 5 1 [print i i: 5] ; this should print 5 and terminate for i 5 5 1 [print i i: 6] ; this should print 5 and terminate | |
It is quite funny that you read what I wrote in the ticket but have got no idea what the differences are | |
similar examples for negative BUMP: for i 5 5 -1 [print i i: 3] ; this should print 5 and terminate for i 5 5 -1 [print i i: 4] ; this should print 5 and terminate for i 5 5 -1 [print i i: 5] ; this should print 5 and terminate for i 5 5 -1 [print i i: 6] ; this should be an infinite loop for i 5 5 -1 [print i i: 7] ; this should print 5 and terminate | |
and as I said for zero bump you do not have any reasonable termination condition to use that would allow you to iterate at least once but not infinitely many times by default, so you just have to terminate before starting | |
Your problem is that you did not realize that the only way how to stop *before* starting is to apply the termination condition *just before* entering the cycle body | |
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